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平行系统方法在自动化集装箱码头中的应用研究

郑松 吴晓林 王飞跃 林东东 郑蓉 柯伟林 池新栋 陈德旺

刘秀翀, 王占山. 系统H∞范数计算:Lyapunov函数的直接优化方法. 自动化学报, 2019, 45(8): 1606-1610. doi: 10.16383/j.aas.c180619
引用本文: 郑松, 吴晓林, 王飞跃, 林东东, 郑蓉, 柯伟林, 池新栋, 陈德旺. 平行系统方法在自动化集装箱码头中的应用研究. 自动化学报, 2019, 45(3): 490-504. doi: 10.16383/j.aas.c170734
LIU Xiu-Chong, WANG Zhan-Shan. Calculation of the System H∞ Norm: a Lyapunov Function Optimization Method. ACTA AUTOMATICA SINICA, 2019, 45(8): 1606-1610. doi: 10.16383/j.aas.c180619
Citation: ZHENG Song, WU Xiao-Lin, WANG Fei-Yue, LIN Dong-Dong, ZHENG Rong, KE Wei-Lin, CHI Xin-Dong, CHEN De-Wang. Applying the Parallel Systems Approach to Automatic Container Terminal. ACTA AUTOMATICA SINICA, 2019, 45(3): 490-504. doi: 10.16383/j.aas.c170734

平行系统方法在自动化集装箱码头中的应用研究

doi: 10.16383/j.aas.c170734
详细信息
    作者简介:

    吴晓林  爱普(福建)科技有限公司自动化集装箱码头控制系统实验室主任.2015年获得福州大学电气工程与自动化学院学士学位.主要研究方向为复杂系统, 多代理系统和自动控制.E-mail:xiaolin.wu@iapcloud.cn

    王飞跃  中国科学院自动化研究所复杂系统管理与控制国家重点实验室主任, 国防科技大学军事计算实验与平行系统技术研究中心主任, 中国科学院大学中国经济与社会安全研究中心主任, 青岛智能产业技术研究院院长.主要研究方向为平行系统的方法与应用, 社会计算, 平行智能以及知识自动化.E-mail:feiyue.wang@ia.ac.cn

    林东东  爱普(福建)科技有限公司自动化集装箱码头控制系统实验室工程师.2013年获得武汉理工大学电气工程与自动化学院学士学位.主要研究方向为AGV协同控制和智能算法.E-mail:dongdong.lin@iapcloud.cn

    郑蓉  爱普(福建)科技有限公司先进控制实验室助理研究员.2012年获得福州大学生物化学和分子生物学硕士学位.主要研究方向为智能生活, 机器人和复杂系统.E-mail:rzheng2017@163.com

    柯伟林  爱普(福建)科技有限公司自动化集装箱码头控制系统实验室工程师.2015年获得福建农林大学电气工程与自动化学院学士学位.主要研究方向为堆场自动化控制及集装箱库存管理.E-mail:weilin.ke@iapcloud.cn

    池新栋  福州大学电气工程与自动化学院研究生.2016年获得华北水利水电学院自动化专业学士学位.主要研究方向为复杂系统控制以及多代理架构在集装箱码头的应用.E-mail:13140163697@163.com

    陈德旺  福州大学数学与计算机科学学院教授.2003年在中国科学院自动化研究所获得控制理论专业博士学位.主要研究方向为智能控制, 机器学习和智能交通系统.E-mail:dwchen@fzu.edu.cn

    通讯作者:

    郑松  福州大学电气工程与自动化学院研究员.2008年获得清华大学热能工程系博士学位.主要研究方向为复杂系统, 工业互联网, 云控制, 机器人和工业信息安全.本文通信作者.E-mail:s.zheng@fzu.edu.cn

Applying the Parallel Systems Approach to Automatic Container Terminal

More Information
    Author Bio:

    Director at the Automatic Container Terminal Control System Laboratory, IAP (Fujian) Technology Co., Ltd. He received his bachelor degree from the Institute of Electrical Engineering and Automation, Fuzhou University in 2015. His research interest covers complex system, multi-agent system, and automatic control

    State specially appointed expert and director of the State Key Laboratory for Management and Control of Complex Systems, Institute of Automation, Chinese Academy of Sciences. Professor of the Research Center for Computational Experiments and Parallel Systems Technology, National University of Defense Technology. Director of China Economic and Social Security Research Center in University of Chinese Academy of Sciences. Dean of Qingdao Academy of Intelligent Industries. His research interest covers methods and applications for parallel systems, social computing, parallel intelligence, and knowledge automation

    Engineer at the Automatic Container Terminal Control System Laboratory IAP (Fujian) Technology Co., Ltd. He received his bachelor degree from the College of Electrical Engineering and Automation, Wuhan University of Technology in 2013. His research interest covers AGV cooperative control and intelligent algorithm

    Assistant researcher at the Advanced Control Laboratory, IAP (Fujian) Technology Co., Ltd. She received her master degree in biochemistry and molecular biology, Fuzhou University in 2012. Her research interest covers smart life, robot, and complex systems

    Engineer at the Automatic Container Terminal Control System Laboratory, IAP (Fujian) Technology Co., Ltd. He received his bachelor degree from the College of Electrical Engineering and Automation, Fujian Agriculture and Forestry University in 2015. His research interest covers yard automation control and container inventory management system

    Master student at the Institute of Electrical Engineering and Automation, Fuzhou University. He received his bachelor degree in automation from North China University of Water Resources and Electric Power in 2016. His research interest covers complex system control and multi-agent architecture in container automation terminals

    Professor at the College of Mathematics and Computer Science, Fuzhou University. He received his Ph. D. degree in control theory from Institute of Automation, Chinese Academy of Sciences in 2003. His current research interests include intelligent control, machine learning, and intelligent transportation systems

    Corresponding author: ZHENG Song Professor at the Institute of Electrical Engineering and Automation, Fuzhou University. He received his Ph. D. degree from the Department of Thermal Engineering, Tsinghua University in 2008. His research interest covers complex systems, industrial internet, cloud control, robotics, and industrial information security. Corresponding author of this paper
  • 摘要: 平行系统是一种建立在人工社会和计算实验基础上的科学研究方法,它的特点是既能真实反映现实系统的动态过程,又能实时优化现实系统的控制过程.自动化集装箱码头是一类典型的复杂系统,既存在不计其数的作业方案,同时也有大量的约束条件.如何在最短时间和最低能源消耗的前提下,完成具有间歇和批次特征的集装箱转运任务,是涉及到数学、控制、管理和计算机等多个学科的重大课题.本文采用数据引擎作为人工社会中的基本计算单元,构成一个复杂的平行系统,用于自动化集装箱码头信息控制系统的研究.数据引擎作为一种面向图形化元件组态的计算环境,非常适用于复杂系统的建模与计算.在可视化和动态重构技术的支持下,利用380个数据引擎对一个具有8台岸桥、25辆AGV和16台龙门吊组成的港机系统进行了自动化作业过程的计算实验.研究结果表明,数据引擎技术是实现平行系统的有效方法,由多数据引擎组成的计算环境,能够大幅度降低自动化集装箱码头信息控制系统建模的复杂程度,能够将码头系统的管理和控制过程无缝地融合在一起.该平行系统可直接与港机设备对接,建立“人工码头”和“物理码头”之间的平行关系,从而实现对港机设备的最优控制.
  • $ H_{\infty} $控制理论主要研究抑制干扰和不确定性问题[1].在$ H_{\infty} $控制理论中, 传递函数(或系统)的$ H_{\infty} $范数是一项重要的性能指标, 用于度量扰动输入对系统输出的影响, 反映了闭环系统的抗扰能力.在$ H_{\infty} $控制理论研究中, 长期存在一个挑战性议题:是否能够直接给出关于$ H_{\infty} $范数的通用解析表达式, 进而避免针对线性矩阵不等式(Linear matrix inequality, LMI)约束条件的繁琐的$ H_{\infty} $范数近似寻优方案.

    在20世纪80年代, $ H_{\infty} $控制理论的研究由频域转换到时域, 开启了基于状态空间方程描述的系统鲁棒性能研究[2].总的来说, $ H_{\infty} $性能时域分析面临的核心问题是如何选择适当的李雅普诺夫函数.具体表现为基于李雅普诺夫方程[3-4]或参数化Riccati不等式[5]均难以得到用于精确分析系统$ H_{\infty} $性能的最优李雅普诺夫函数, 因此在早期的研究中结果的保守性是难以避免的.

    为精确求解$ H_{\infty} $范数, 有学者提出了有界实引理[6], 并将求解$ H_{\infty} $范数问题转化为时域状态空间的约束优化问题.基于有界实引理给出的LMI约束条件, $ H_{\infty} $范数能够被近似寻优[7-14].在LMI方法中, $ H_{\infty} $范数的寻优一般包含以下步骤:

    1) 给出一个充分大的初始$ H_{\infty} $范数估计$ \mit\gamma $;

    2) 解LMI问题;

    3) 递减$ H_{\infty} $范数估计$ \mit\gamma $, 直到获得满足LMI条件的最小$ H_{\infty} $范数估计$ \mit\gamma $.

    显然, 一旦最小$ H_{\infty} $范数估计得到, 则通过解LMI, 可以得到相应的近似最优李雅普诺夫函数.不难发现, LMI方法存在一定不足, 表现为:

    1) 对于每一个给定的$ \mit\gamma $, LMI条件需要被重复求解, 直到找到最小的$ H_{\infty} $范数估计, 过程过于繁琐;

    2) 这种试凑逼近方法无法揭示系统结构和参数对$ H_{\infty} $性能的影响, 在一定程度上限制了控制器精细设计的研究.

    为了克服目前关于$ H_{\infty} $范数问题研究的不足, 一个可替换的方法是直接优化李雅普诺夫函数, 进而得到关于$ H_{\infty} $范数的通用解析表达式.目前, 针对系统具体性能, 难以找到李雅普诺夫函数设计的充要条件, 因此这方面的研究并不多见.事实上, 在分析系统具体性能时, 存在最优的李雅普诺夫函数, 并且这一最优李雅普诺夫函数与系统结构和参数存在内在关系[15].因此本文尝试寻找一种李雅普诺夫函数的直接优化途径, 进而实现$ H_{\infty} $性能的精确分析.

    由于多数高阶系统在一定的条件下可以近似(或分解)为二阶系统来研究, 并且二阶系统的分析方法是分析高阶系统的基础[16], 因此为有效展现最优李雅普诺夫函数与系统结构和参数存在内在关系, 本文针对一类二阶系统的$ H_{\infty} $范数问题, 构造和优化李雅普诺夫函数, 进而得到$ H_{\infty} $范数的通用解析表达式.本文的研究避免了LMI方法中繁琐的近似寻优过程, 并展示了系统矩阵特征值的实部和虚部对$ H_{\infty} $性能的影响.本文结构如下:第1节分析$ H_{\infty} $范数问题; 第2节分析Riccati不等式中李雅普诺夫函数的选择对求解$ H_{\infty} $范数的影响; 第3节展现李雅普诺夫函数的直接优化方法, 并给出$ H_{\infty} $范数的通用解析表达式; 第4节给出算例, 验证李雅普诺夫函数直接优化方法的有效性.

    系统描述为

    $ \begin{align} \dot{\boldsymbol{ x}} = A {\boldsymbol{ x}}+ {\boldsymbol{ w}} \end{align} $

    (1)

    其中, $ {\boldsymbol{ x}} \in \textbf{R}^{2} $, $ A $为Hurwitz矩阵, $ A $的特征值为复数, $ {\boldsymbol{ w}} $为扰动输入, $ \|{\boldsymbol{ w}}\| \leq \delta $, $ \delta $为常数, $ \|{\boldsymbol{ w}}\| = (\Sigma^{2}_{i = 1}w^{2}_{i})^{\frac{1}{2}} $.

    研究的问题是如何得到系统(1)的状态上界.在数学意义上, 这一问题可转化为关于输入–输出系统的$ H_{\infty} $范数问题, 其中系统描述为

    $ \begin{align} \begin{cases} \dot{\boldsymbol{ x}} = A {\boldsymbol{ x}} + {\boldsymbol{ w}} \\ {\boldsymbol{ y}} = {\boldsymbol{ x}} \end{cases} \end{align} $

    (2)

    在$ H_{\infty} $控制理论中, 系统的$ H_{\infty} $范数定义为$ S $右半平面上解析的有理函数阵的最大奇异值.在标量函数中就是幅频特性的极大值, 代表了系统对峰值有界信号的传递特性.

    令李雅普诺夫函数为$ V = {\boldsymbol{ x}}^{\rm T}P{\boldsymbol{ x}} $, $ \gamma $为系统(2)的$ H_{\infty} $范数, 即$ \mit\gamma = \|G\|_{\infty} $, 其中$ G(s) = (sI-A)^{-1} $为系统(2)的传递函数.根据有界实引理, 可得

    $ \begin{align} \left[ \begin{array}{ccc} PA+A^{\rm{T}}P & P & I \\ P & -\gamma^{2} I & 0_{2\times 2} \\ I & 0_{2\times 2} & -I \\ \end{array} \right] < 0 \end{align} $

    (3)

    LMI方法是寻找式(3)中$ \mit\gamma $的最小值$ \mit\gamma_{\rm{min}} $.由于李雅普诺夫函数$ V = {\boldsymbol{ x}}^{\rm T}P {\boldsymbol{ x}} $可以任意构造, 因此对于每一个给定的$ \mit\gamma $, 需要重复求解LMI, 以判断式(3)的存在性, 直到$ \mit\gamma_{\rm{min}} $被找到.显然, 在LMI方法中复杂的优化过程是不可避免的.事实上, $ \mit\gamma_{\rm{min}} $与最优的$ P $矩阵是一一对应的.如果能够直接给出最优的$ P $矩阵, 则$ \mit\gamma_{\rm{min}} $的表达式就能够得到, 进而避免LMI方法中复杂的优化过程.本文的工作是尝试提供一种新的途径来直接给出$ \mit\gamma_{\rm{min}} $的表达式.

    根据特征值和奇异值分解原理, 可以得到下面的特性.

    特性1. 对于系统(2)中特征矩阵$ A $, 存在可逆矩阵$ T $, 满足

    $ \begin{align} D = -TAT^{-1} = \left[ \begin{array}{cc} \lambda & \nu \\ -\nu & \lambda \\ \end{array} \right] \end{align} $

    (4)

    其中, $ T = \Theta_{T1} \times \text{diag}\{t_{1}, t_{2}\} \times \Theta_{T2} $, $ \Theta_{T1} $和$ \Theta_{T2} $为正交矩阵, $ t_{2} \geq t_{1} > 0 $, $ \lambda > 0 $, $ \nu > 0 $. $ \text{diag}\{t_{1}, t_{2}\} $表示对角元素为$ t_{1} $, $ t_{2} $的对角阵.

    令$ \alpha = {t_{2}}/{t_{1}} \geq 1 $, $ {\boldsymbol{ y}} = \Theta_{T2} \times {\boldsymbol{ x}} $, $ {\boldsymbol{ {\Delta}}} = \Theta_{T2}\times{\boldsymbol{ w}} $.由式(2)和特性1, 得

    $ \begin{align} \begin{cases} \dot{\boldsymbol{ y}} = E {\boldsymbol{ y}} + B {\boldsymbol{ {\Delta}}} \\ {\boldsymbol{ x}} = C {\boldsymbol{ y}} \end{cases} \end{align} $

    (5)

    其中, $ B = I $为单位阵, $ C = \Theta_{T2}^{-1} $, $ E = - \left[ {array}{cc} \lambda & \alpha \nu \\ -\frac{1}{\alpha}\nu & \lambda \\ {array} \right], $并且系统(2)和(5)具有相同的$ H_{\infty} $范数.

    根据文献[5]中引理2.1, 可以得到下面的特性.

    特性2. 对于系统(5), 存在正定矩阵$ X $, 满足Riccati不等式

    $ \begin{align} E^{\rm T}X+XE+(1+\varepsilon)C^{\rm T}C+ \rho^{-2} XBB^{\rm T}X \leq 0 \end{align} $

    (6)

    其中, $ \gamma < \rho $, $ \gamma = \|G\|_{\infty} $为系统$ H_{\infty} $范数, $ \varepsilon $为趋于零的正数.

    注1. 应用Riccati不等式一般会得到具有很强保守性的结果, 但这种保守性并不是Riccati不等式本身导致的.研究表明:基于李雅普诺夫函数的准确选择, 可以将特性2中Riccati不等式转化为等式, 进而精确给出$ H_{\infty} $范数.因此, 导致这种保守性的原因是:在应用Riccati不等式时, 目前尚没有有效的方法找到最优的李雅普诺夫函数.这正是本文研究李雅普诺夫函数构造(或优化)的动机.

    $ \begin{align} \Upsilon = \, &K^{-1} \Theta \begin{bmatrix} \lambda & -\frac{1}{\alpha} \nu \\ \alpha \nu & \lambda \end{bmatrix}\Theta^{\rm T}\; + \nonumber \\&\Theta \begin{bmatrix} \lambda & \alpha \nu \\ -\frac{1}{\alpha} \nu & \lambda \\ \end{bmatrix} \Theta^{\rm T}K^{-1} - K^{-1}K^{-1} \end{align} $

    (7)

    其中, $ \alpha \geq 1 $,

    $ \begin{align} K = \iota \left[ \begin{array}{cc} 1 & 0 \\ 0 & k \\ \end{array} \right], \;\;\;\; \Theta = \left[ \begin{array}{cc} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \\ \end{array} \right] \end{align} $

    (8)

    $ \iota >0 $, $ k \geq 1 $, $ 0 \leq \theta \leq {\pi}/{4} $.

    由式(8)构造的李雅普诺夫函数分解了"放缩"和"旋转"作用.这种功能的分解使李雅普诺夫函数的参数优化具有了可行性.

    定理1. 对于系统(5), 系统$ H_{\infty} $范数$ \gamma $满足

    $ \begin{align} \gamma < \rho_{\rm{min}} = \left[\sqrt{\lambda_{\rm{min}}(\Upsilon)} \right]^{-1} \end{align} $

    (9)

    其中, $ \lambda_{\rm{min}}(\Upsilon) $为矩阵$ \Upsilon $的最小特征值.

    证明. 令$ X = \Theta^{\rm T} K \Theta $, 其中, $ K $和$ \Theta $由式(8)给出.根据特性2和式(7), 得

    $ \begin{align} \rho^{-2} I \leq \Upsilon - \varepsilon K^{-1}K^{-1} \end{align} $

    (10)

    则$ \rho^{-2} \leq \lambda_{\rm{min}}(\Upsilon- \varepsilon K^{-1}K^{-1}) $, 由于$ \gamma < \rho $, 并且$ \varepsilon $为趋于零的正数, 则式(9)成立.

    注2. 根据定理1, 可以优化李雅普诺夫函数的参数, 以最大化$ \lambda_{\rm{min}}(\Upsilon) $, 进而精确估计系统$ H_{\infty} $范数.因此, 定理1给出了一种新的途径以得到系统的$ H_{\infty} $范数.

    考查式(7)给出的矩阵$ \Upsilon $.由式(7)和式(8), 可得

    $ \begin{align} \Upsilon = \frac{1}{\iota} \left[ \begin{array}{cc} 2\lambda + \beta \nu - \frac{1}{\iota} & \frac{1}{k} \sigma \nu \\ \frac{1}{k} \sigma \nu & \frac{1}{k}(2 \lambda - \beta \nu) - \frac{1}{\iota k^{2}} \\ \end{array} \right] \end{align} $

    (11)

    其中,

    $ \begin{align} \beta = &\ \left(\alpha-\frac{1}{\alpha}\right) \sin 2\theta \end{align} $

    (12)

    $ \begin{align} \sigma = &\, \left[\alpha- (\alpha-\frac{1}{\alpha}) \sin^{2} \theta \right] -k \left[\frac{1}{\alpha} + (\alpha-\frac{1}{\alpha}) \sin^{2} \theta \right] = \\ &\ \frac{1}{2}(1-k)(\alpha+\frac{1}{\alpha}) +\frac{1}{2}(1+k) (\alpha-\frac{1}{\alpha}) \cos 2\theta \end{align} $

    (13)

    根据式(11), 以最大化$ \lambda_{\rm{min}}(\Upsilon) $为目标, 将给出一种李雅普诺夫函数的优化方法.

    $ \begin{align} \Upsilon_{1} = \Theta^{-1} \Upsilon \Theta, \; \; Y_{1} = X^{-1} \end{align} $

    (14)

    则由式(7)和$ X = \Theta^{\rm T}K\Theta $, 得

    $ \begin{align} \Upsilon_{1} = EE^{\rm T}-(E+Y_{1})(E+Y_{1})^{\rm T} \end{align} $

    (15)

    $ \begin{align} &EE^{\rm T} = \Theta_{1}^{\rm T} \Lambda \Theta_{1}, \quad \Upsilon_{2} = \Theta_{1} \Upsilon_{1} \Theta_{1}^{\rm T} \end{align} $

    (16)

    $ \begin{align} &E_{1} = \Theta_{1} E \Theta_{1}^{\rm T}, \qquad Y_{2} = \Theta_{1} Y_{1} \Theta_{1}^{\rm T} \end{align} $

    (17)

    其中, $ \Lambda = {\rm diag}\{\sigma_{1}, \sigma_{2}\} $, $ \sigma_{1} \geq \sigma_{2} $, 则

    $ \begin{align} \Upsilon_{2} = \Lambda - (E_{1}+Y_{2})(E_{1}+Y_{2})^{\rm T} \end{align} $

    (18)

    $ \begin{align} E_{1} = E_{R}+E_{J}, \; \; Y_{3} = E_{R}+Y_{2} \end{align} $

    (19)

    其中, $ E_{R}^{\rm T} = E_{R} $, $ E_{J} = -E_{J}^{\rm T} $, 则

    $ \begin{align} \Upsilon_{2} = \Lambda - (E_{J}+Y_{3})(E_{J}+Y_{3})^{\rm T} \end{align} $

    (20)

    $ \begin{align} Y_{3} = \left[ \begin{array}{cc} y_{1} & y_{3} \\ y_{3} & y_{2} \\ \end{array} \right], \; \; E_{J} = \left[ \begin{array}{cc} 0 & a \\ -a & 0 \\ \end{array} \right] \end{align} $

    (21)

    则根据$ \Lambda = \text{diag}\{\sigma_{1}, \sigma_{2}\} $, 有$ \sigma_{1} \geq \sigma_{2} $,

    $ \begin{align} \Upsilon_{2} = & \left[ \begin{array}{cc} \sigma_{1}-(y_{3}+a)^{2}-y_{1}^{2} \\ -(y_{1}+y_{2})y_{3}-(y_{2}-y_{1})a \\ \end{array}\right.\\ &\qquad\qquad\qquad \left. \begin{array}{cc} & -(y_{1}+y_{2})y_{3}-(y_{2}-y_{1})a \\ & \sigma_{2} -(y_{3}-a)^{2}-y_{2}^{2} \\ \end{array} \right] \end{align} $

    (22)

    根据式(14), (16), (21), (22)和定理1, 存在$ Y_{3} $, 使$ \lambda_{\rm{min}}(\Upsilon_{2}) $ $ > $ $ 0 $, 即$ \Upsilon_{2} $正定.因此根据式(22), 为了最大化$ \Upsilon_{2} $的最小特征值, 应使下面两个条件成立.

    1) $ (y_{1}+y_{2})y_{3}+ (y_{2}-y_{1})a = 0 $ (例如$ y_{2} = 0 $, $ y_{3} = a $; 或$ y_{1} = y_{2} = 0 $).

    2) $ \Upsilon_{2} $的特征值相等(例如$ y_{1}^{2} = \sigma_{1}-\sigma_{2}-4a^{2} $; 或$ y_{3} $ $ = $ $ (\sigma_{1}-\sigma_{2})/{4a} $).

    注意, $ \sqrt{\sigma_{2}} $为$ E $的最小奇异值, 因此$ \gamma \geq {1}/{\sqrt{\sigma_{2}}} $.令

    $ \begin{align} \lambda_{1} = \frac{1}{\iota}\left( 2\lambda + \beta \nu - \frac{1}{\iota} \right), \; \; \lambda_{2} = \frac{1}{\iota}\left[ \frac{1}{k}(2 \lambda - \beta \nu) - \frac{1}{\iota k^{2}} \right] \end{align} $

    (23)

    基于以上分析, 并根据式(9), (11), (14), (16)和(23), 为了最大化$ \Upsilon $的最小特征值, 李雅普诺夫函数的优化策略设计为$ \sigma = 0 $和$ \lambda_{1} = \lambda_{2} $.

    基于所给李雅普诺夫函数优化策略, 进一步优化李雅普诺夫函数参数.

    定理2. 对于系统(5), 系统$ H_{\infty} $范数$ \gamma $满足

    $ \begin{align} \gamma < \rho(k, \iota) = \left[\min(\lambda_{1}, \lambda_{2}) \right]^{-\frac{1}{2}} \end{align} $

    (24)

    其中, $ \lambda_{1} $和$ \lambda_{2} $由式(23)给出, 式(23)中$ \beta $由下式给出.

    $ \begin{align} \beta = \frac{2}{k+1}\sqrt{\left(k \alpha-\frac{1}{\alpha}\right)\left(\alpha- \frac{k}{\alpha}\right)} \end{align} $

    (25)

    证明. 考查式(11)给出的矩阵$ \Upsilon $.令$ \sigma = 0 $, 则

    $ \begin{align} \cos 2\theta = \frac{(k-1)(\alpha+\frac{1}{\alpha})}{(k+1)(\alpha-\frac{1}{\alpha})} \end{align} $

    (26)

    因此根据式(11), (12), (23)和$ 0 \leq \theta \leq {\pi}/{4} $, 矩阵$ \Upsilon $的特征值为$ \lambda_{1} $和$ \lambda_{2} $, 其中$ \beta $由式(25)给出.根据定理1, 可得式(24).

    注3. 基于李雅普诺夫函数参数矩阵$ \Theta $的优化策略, 定理2进一步给出系统$ H_{\infty} $范数的估计., 同时奠定了进一步优化李雅普诺夫函数参数$ k $和$ \iota $的基础.

    定理3. 对于系统(5), 系统$ H_{\infty} $范数$ \gamma $满足

    $ \begin{align} \gamma < \rho(k) = \begin{cases} \frac{1}{\lambda}, & \text{若}\; \alpha = 1\\ \left[ f(k)\right]^{-\frac{1}{2}}, & \text{若}\; \alpha >1 \end{cases} \end{align} $

    (27)

    其中,

    $ \begin{align} f(k) = \frac{4k}{(k+1)^{2}} \left[ \lambda^{2} + \nu^{2} - \frac{k \nu^{2}}{(k-1)^{2}} \left(\alpha-\frac{1}{\alpha}\right)^{2} \right] \end{align} $

    (28)

    证明. 考查式(23)给出的矩阵$ \Upsilon $的特征值为$ \lambda_{1} $和$ \lambda_{2} $.令$ \lambda_{1} = \lambda_{2} $, 即

    $ \begin{align} 2\lambda + \beta \nu - \frac{1}{\iota} = \frac{1}{k}(2 \lambda - \beta \nu) - \frac{1}{\iota k^{2}} \end{align} $

    (29)

    其中, $ \beta $由式(25)给出, $ \alpha \geq 1 $.

    当$ \alpha > 1 $时, 由式(25)和式(29)可知$ k \neq 1 $, 并且得

    $ \begin{align} \frac{1}{\iota} = \frac{2k \lambda}{k+1}+\frac{2k \nu}{k^{2}-1} \sqrt{\left(k \alpha- \frac{1}{\alpha}\right)\left(\alpha-\frac{k}{\alpha}\right)} \end{align} $

    (30)

    当$ \alpha = 1 $时, 由式(25)可知$ (k-1)^{2} \leq 0 $, 即$ k = 1 $.则根据式(23), (25), (29), $ \lambda_{1} = \lambda_{2} = \frac{1}{\iota} (2 \lambda-\frac{1}{\iota}) $.当$ \iota = \lambda $时, 得$ \max (\lambda_{1}) = \lambda^{2} $.

    基于以上分析, 并根据定理2和式(23), (25), (29)以及(30), 可得结论.

    注4. 通过给出李雅普诺夫函数参数$ \iota $的优化策略, 定理3进一步给出系统$ H_{\infty} $范数的估计.根据定理3, 可以直接优化李雅普诺夫函数参数$ k $, 进而得到系统$ H_{\infty} $范数的精确估计.

    注5. 注意, 当$ \alpha > 1 $时, $ k \neq 1 $.因此定理3通过分别讨论$ \alpha > 1 $和$ \alpha = 1 $两种情况, 解决了$ f(k) $的奇异问题.

    $ \begin{align} \kappa = k + \frac{1}{k} > 2 \end{align} $

    (31)

    则由式(28), 得

    $ \begin{align} f(\kappa) = \frac{4(\lambda^{2} + \nu^{2})}{\kappa+2} - \frac{4\nu^{2}}{\kappa^{2}-4} \times \left(\alpha-\frac{1}{\alpha}\right)^{2} \end{align} $

    (32)

    定理4. 对于系统(5), 系统$ H_{\infty} $范数$ \gamma $满足

    $ \begin{align} \gamma < \rho_{\text{opt}} = \begin{cases} \frac{1}{\lambda}, & \text{若}\; \alpha = 1\\ \frac{1}{2\lambda}\sqrt{\alpha^{2}+\frac{1}{\alpha^{2}}+2}, &\text{若}\; \kappa_{0} \geq \alpha^{2}+\frac{1}{\alpha^{2}}\\ \left[ f(\kappa_{0})\right]^{-\frac{1}{2}}, &\text{若}\; \kappa_{0} < \alpha^{2}+\frac{1}{\alpha^{2}} \end{cases} \end{align} $

    (33)

    其中

    $ \begin{align} &f(\kappa_{0}) = \frac{4(\lambda^{2} + \nu^{2})}{\kappa_{0}+2} - \frac{4\nu^{2}}{\kappa_{0}^{2}-4} \times \left(\alpha-\frac{1}{\alpha}\right)^{2} \end{align} $

    (34)

    $ \begin{align} &\kappa_{0} = 2 + \frac{\nu^{2} (\alpha-\frac{1}{\alpha})^{2}}{\lambda^{2} + \nu^{2}} \times \left[ 1+\sqrt{1+ \frac{4(\lambda^{2} + \nu^{2})}{\nu^{2} (\alpha-\frac{1}{\alpha})^{2}}} \right] \end{align} $

    (35)

    证明. 由式(32), 得

    $ \begin{align} f'(\kappa) = \frac{{\rm d} f(\kappa)}{{\rm d} \kappa} = -\frac{4(\lambda^{2} + \nu^{2})}{(\kappa+2)^{2}} +\frac{8(\alpha-\frac{1}{\alpha})^{2} \nu^{2} \kappa}{(\kappa+2)^{2}(\kappa-2)^{2}} \end{align} $

    (36)

    令$ f'(\kappa) = 0 $, 即

    $ \begin{align} \kappa^{2} - \left[ 4+ \frac{2(\alpha-\frac{1}{\alpha})^{2} \nu^{2}}{\lambda^{2} + \nu^{2}} \right] \kappa +4 = 0 \end{align} $

    (37)

    根据$ \kappa >2 $和式(35), 得$ \kappa = \kappa_{0} $.

    根据式(35) $ \sim $ (37), 得

    $ \begin{align} \lim \limits_{\varsigma \rightarrow 0} \frac{f'(\kappa_{0} + \varsigma)-f'(\kappa_{0})}{\varsigma} <0 \end{align} $

    (38)

    因此, 在$ 2 < \kappa < \infty $的条件下, $ \max f(\kappa) = f(\kappa_{0}) $, 如图 1 (a)1 (b)所示.

    图 1  函数分析
    Fig. 1  Function analysis

    注意, 定理2中李雅普诺夫函数参数矩阵$ \Theta $的优化策略为$ \sigma = 0 $, 则由式(13), 可得$ k \leq \alpha^{2} $.由于$ k >1 $, 因此根据式(31), 得

    $ \begin{align} \Omega = \left\{ \kappa \in \textbf{R} | 2 < \kappa \leq \alpha^{2}+\frac{1}{\alpha^{2}} \right\} \end{align} $

    (39)

    根据图 1 (a)1 (b), 得

    $ \begin{align} \max \limits_{k \in \Omega} f(\kappa) = \begin{cases} \frac{4\lambda^{2}}{\alpha^{2}+\frac{1}{\alpha^{2}}+2}, &\text{若}\; \kappa_{0} \geq \alpha^{2}+\frac{1}{\alpha^{2}}\\ f(\kappa_{0}), & \text{若}\; \kappa_{0} < \alpha^{2}+\frac{1}{\alpha^{2}} \end{cases} \end{align} $

    (40)

    因此由定理3可得结论.

    注6. 通过对李雅普诺夫函数参数的直接优化, 定理4给出了系统$ H_{\infty} $范数上界的优化结果.应用定理4, 可以给出系统$ H_{\infty} $范数的精确估计.

    注7. 不同于LMI方法, 本文提出的李雅普诺夫函数直接优化方法分析了李雅普诺夫函数的构造对系统性能分析的影响, 充分利用系统结构和参数以优化李雅普诺夫函数的设计.与LMI方法相比, 李雅普诺夫函数直接优化方法能够直接给出系统$ H_{\infty} $范数的精确结果, 进而避免了复杂的数值优化过程.因此本文的工作提供了一种新的途径以更为方便地分析系统动态性能.

    考查系统

    $ \begin{align} \dot{\boldsymbol{ x}} = -\left[ \begin{array}{cc} 1.25 & 1.25 \\ -1.25 & 2.75 \\ \end{array} \right]{\boldsymbol{ x}}+ {\boldsymbol{ w}} \end{align} $

    (41)

    其中, $ {\boldsymbol{ w}} $为扰动输入, $ \|{\boldsymbol{ w}}\| \leq 1 $, $ {\boldsymbol{ x}} $为状态输出.根据式(5), 得

    $ \begin{align} \begin{cases} \dot{\boldsymbol{ y}} = - \left[ \begin{array}{cc} 2 & 2 \\ -0.5 & 2 \\ \end{array} \right] {\boldsymbol{ y}} + {\boldsymbol{ {\Delta}}} \\ {\boldsymbol{ x}} = \frac{\sqrt{2}}{2} \left[ \begin{array}{cc} 1 & -1 \\ 1 & 1 \\ \end{array} \right] {\boldsymbol{ y}} \end{cases} \end{align} $

    (42)

    因此, $ \lambda = 2 $, $ \nu = 1 $, $ \alpha = 2 $.

    由式(34), 得$ \kappa_{0} = 3.8651< \alpha^{2}+\frac{1}{\alpha^{2}} = 4.25 $.则根据定理4, 得$ \gamma < \rho_{\text{opt}} = 0.622 $.因此$ \gamma \approx 0.622 $.应用MATLAB中$ H_{\infty} $范数求解函数hinfnorm (sys, 0.0000001)可得相同的结果.因此提出的李雅普诺夫函数直接优化方法能精确给出系统$ H_{\infty} $范数.

    表 1进一步给出在不同参数条件下系统(5)的$ H_{\infty} $范数.表 1表明, 针对式(5)给出的具有不同参数的系统, 提出的李雅普诺夫函数直接优化方法都能精确给出系统$ H_{\infty} $范数.

    表 1  $H_{\infty}$范数分析($\alpha = 2$)
    Table 1  $H_{\infty}$ norm analysis ($\alpha = 2$)
    $\lambda$ $\nu$ MATLAB 定理4 稳态误差$\|A^{-1}\|$ 状态上界
    2 6 0.626 0.626 0.307 0.626
    2 4 0.626 0.626 0.419 0.626
    2 2 0.626 0.626 0.588 0.626
    2 1.2 0.626 0.626 0.626 0.626
    2 1 0.622 0.622 0.622 0.622
    2 0 0.501 0.501 0.501 0.501
    下载: 导出CSV 
    | 显示表格

    在$ \alpha $和系统特征值实部$ \lambda $确定(即$ \alpha = 2 $, $ \lambda = 2 $)的条件下, 表 1给出的结果表明, 随着系统特征值虚部$ \nu $变化, $ H_{\infty} $范数的变化具有一定规律性, 表现为:

    1) 当$ \nu = \nu^{*} = 1.2 $ (即$ \kappa_{0} = \alpha^{2}+{1}/{\alpha^{2}} $)时, $ H_{\infty} $范数为$ \max \|A^{-1}\| $;

    2) 当$ \nu < \nu^{*} $ (即$ \kappa_{0} < \alpha^{2}+{1}/{\alpha^{2}} $)时, $ H_{\infty} $范数与稳态指标$ \|A^{-1}\| $一致;

    3) 当$ \nu > \nu^{*} $ (即$ \kappa_{0} > \alpha^{2}+{1}/{\alpha^{2}} $)时, $ H_{\infty} $范数为固定值(即$ H_{\infty} $范数的值与$ \nu $无关), 并且根据定理4, $ H_{\infty} $范数的表达式非常简洁.

    由式(1), (3), (41), 得

    $ \begin{align} \begin{bmatrix} -P \begin{bmatrix} 1.25 & 1.25 \\ -1.25 & 2.75 \\ \end{bmatrix} -\small{ \begin{bmatrix} 1.25 & -1.25 \\ 1.25 & 2.75 \\ \end{bmatrix}}P & P & I \\ P & -\gamma^{2} I & 0_{2\times 2} \\ I & 0_{2\times 2} & -I \end{bmatrix} < 0 \end{align} $

    (43)

    采用LMI方法求解$ H_{\infty} $范数的步骤为:

    1) 选择足够大的$ \gamma $, 如$ \gamma = 10 $;

    2) 应用MATLAB中LMI工具求解式(43), 可得$ P $存在;

    3) 减小$ \gamma $取值, 如$ \gamma = 1 $, 应用LMI工具求解式(43), 可得$ P $存在;

    4) 当$ \gamma = 0.622 $时, 应用LMI工具求解式(43), 可得$ P $存在;

    5) 当$ \gamma = 0.621 $时, 应用LMI工具求解(43), 可得$ P $不存在.

    基于以上步骤, LMI方法可给出$ H_{\infty} = 0.622 $.这一结果与定理4得到的结果一致, 如表 1所示.

    事实上, LMI方法需要对$ \gamma $进行遍历寻找.当选$ \gamma $的间隔较大时, 保守的结果不可避免.与之相比, 本文的方法具有明显的优越性.

    本文针对$ H_{\infty} $控制理论研究中难以精确求解系统$ H_{\infty} $范数的问题, 提出了一种李雅普诺夫函数的直接优化方法.通过优化Riccati不等式中的李雅普诺夫函数, 给出了$ H_{\infty} $范数的通用解析表达式, 进而提供了一个有效的途径以直接和精确求解系统$ H_{\infty} $范数.研究结果具有以下特点:

    1) 与LMI方法相比, 本文所提方法避免了复杂的数值优化过程, 使求解系统$ H_{\infty} $范数简化.

    2) 与早期关于李雅普诺夫方程和Riccati不等式的研究相比, 本文所提方法避免了由于李雅普诺夫函数选择的随意性导致的保守结果.

    3) 本文所提方法能够展现系统矩阵特征值的实部和虚部对$ H_{\infty} $性能的影响, 为进一步精确(定量)控制系统$ H_{\infty} $性能提供借鉴.

    在进一步的工作中, 将研究含有时滞及非线性项的系统.


  • 本文责任编委 魏庆来
  • 图  1  平行控制的基本原理

    Fig.  1  The basic principle of parallel control

    图  2  数据引擎原理

    Fig.  2  The principle of data engine

    图  3  平行码头的架构原理

    Fig.  3  The architecture of parallel container terminal

    图  4  PCTICS系统构成及其应用示例

    Fig.  4  The PCTICS function and examples

    图  5  卸船基本模型的原理

    Fig.  5  The basic model of the discharge process

    图  6  卸船模型的应用实例: AGV代理与车道代理的动态交互

    Fig.  6  An application example of the discharge model: The dynamic interaction among AGV agents and lane agents

    图  7  双车避让规则及其算法实现

    Fig.  7  The implementation of double-car avoidance algorithm

    图  8  PCTICS系统设计及结构

    Fig.  8  The design and structure of PCTICS

    图  9  人工码头集装箱卸船的动态过程

    Fig.  9  The dynamic process of PCTICS discharge

    图  10  人工码头装卸效率

    Fig.  10  The efficiency of PCTICS

    图  11  控制策略变化产生的影响

    Fig.  11  The effect of AGV control strategy changes

    图  12  平行码头中人机交互系统工程应用实例

    Fig.  12  An application example of PCTICS human-computer interaction system

    表  1  不同行驶策略下AGV的任务时耗(s) $^{1}$

    Table  1  The time cost of AGV task under different driving strategies (s) $^{1}$

    $T_{\rm mode 1}$ $T'_{\rm mode 1}$ $T_{\rm mode 2}$ $T'_{\rm mode 2}$
    (Task 1)(Task 2)(Task 1)(Task 2)
    251316243328
    267320245315
    284330253301
    256349254322
    257328253327
    432334260320
    526328261457
    468304248533
    318323265450
    241323276322
    $^{1}$Task 1表示从104号岸桥搬运10个集装箱至47号堆场, Task 2表示从105号岸桥搬运10个集装箱至49号堆场; $T_{\rm mode 1}$和$T'_{\rm mode 1}$分别表示无汇流行驶策略下AGV完成任务1和任务2的时耗; $T_{\rm mode 2}$和$T'_{\rm mode 2}$分别表示汇流行驶策略下AGV完成任务1和任务2的时耗.
    下载: 导出CSV
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